Question

Evaluate f(x) = e^3x+1 when x = 1. (Round to three decimal places.) Provide your answer below: f(1) =

Answer 1

Given the function :

$f(x)=e^{3x}+1$

We need to evaluate the function when x = 1

so,

$\begin{gathered} f(1)=e^{3\cdot1}+1=e^3+1=20.0855+1=21.086 \\ \\ f(1)=21.086 \end{gathered}$

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If the given function is :

$f(x)=e^{3x+1}$

so,

$f(1)=e^{3\cdot1+1}=e^{3+1}=e^4=54.598$