Question

what is the center and radius for the circle with equation (x+9)^2 + y^2 = 1

Answer 1

The general form of the circle is,

$(x-a)^2+(y-b)^2=r^2$

Comparing the given equation with the above equation,

$(x-(-9))^2+(y-0)^2=1^2$

Thus, the required center is (-9,0) and radius is 1.