What is the equation of a line that goes through the point(0, 5/6) and has a slope of 1?

Using the point-slope formula in order to obtain the equation of the line.
The formula is,
[tex]y-y_1=m\left(x-x_1\right)[/tex]Given:
[tex]\begin{gathered} \lparen x_1,y_1)=\left(0,\frac{5}{6}\right) \\ m=1 \end{gathered}[/tex]Therefore,
[tex]y-\frac{5}{6}=1\left(x-0\right)[/tex]Simplify
[tex]\begin{gathered} y-\frac{5}{6}=1\left(x\right) \\ y-\frac{5}{6}=x \\ \therefore y=x+\frac{5}{6} \end{gathered}[/tex]Hence, the equation is
[tex]y=x+\frac{5}{6}\text{ \lparen OPTION 1\rparen}[/tex]