Question

Drag the tiles to the correct boxes to complete the pairs.

Answer 1

Answer::

$\begin{gathered} q(x)=x^2-4x+1 \\ r(x)=0 \\ b(x)=x-3 \end{gathered}$

Explanation:

Given the quotient:

$\frac{x^{3}-7 x^{2}+13 x-3}{x-3}$

We want to rewrite the quotient in the form:

$q(x)+\frac{r(x)}{b(x)}$

First, we use the long division method to first divide.

Therefore:

$\frac{x^{3}-7x^{2}+13x-3}{x-3}=x^2-4x+1+\frac{0}{x-3}$

We thus have the following:

$\begin{gathered} q(x)=x^2-4x+1 \\ r(x)=0 \\ b(x)=x-3 \end{gathered}$