Question

Consider the linear equation:2y + 3 = 0Step 1 of 2: Find two points on the line to be graphed.

Answer 1

Given the linear equation

$2y+3=0$

To begin with, let us make y the subject of the question

$\begin{gathered} 2y=0-3 \\ 2y=-3 \\ \\ y=-\frac{3}{2} \end{gathered}$

The graph of the function is given below

The points on the graph include

$(0,-1.5)\text{ and (3,-1.5)}$

For fraction we will have

$(0,-\frac{3}{2})\text{ and (}3,-\frac{3}{2}\text{)}$