Find all real zeros (if any) and state the multiplicity of each

SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Write the given function
[tex]f(x)=x^6(x-4)^4(x+9)[/tex]STEP 2: Define zeroes of a function
The zeros of a function are the values of x when f(x) is equal to 0. Find x such that f(x)=0
For the given function, the zeroes can be gotten as:
[tex]\begin{gathered} x=0 \\ (x-4)=0,x-4=0,x=0+4,x=4 \\ (x+9)=0,x+9=0,x=0-9,x=-9 \end{gathered}[/tex]STEP 3: Get the multiciplicity
The multiplicity of each zero is the number of times that its corresponding factor appears. In other words, the multiplicities are the powers.
[tex]\begin{gathered} x^6\Rightarrow\text{ multiciplicity is 6} \\ (x-4)^4\Rightarrow\text{multiciplicity is }4 \\ (x+9)\Rightarrow\text{multiciplicity is }1 \end{gathered}[/tex]Hence, the real zeroes and the multiciplicity of the function are:
[tex]\begin{gathered} 0,6 \\ 4,4 \\ -9,1 \end{gathered}[/tex]