Okay, here we have this:
Considering the provided polar equation, we are going to convert it to a rectangular equation, so we obtain the following:
Start by multiplying both sides by r.
[tex]\begin{gathered} r=-4sin(\theta) \\ r^2=-4rsin(\theta) \end{gathered}[/tex]Remember that r²=x²+y²:
[tex]x^2+y^2=-4r\sin (\theta)[/tex]Keep in mind that y=rsinθ:
[tex]\begin{gathered} x^2+y^2=-4y \\ x^2+y^2+4y=0 \end{gathered}[/tex]And finally we complete the square:
[tex]\begin{gathered} x^2+(y^2+4y+4)=4 \\ x^2+(y+2)^2=4 \end{gathered}[/tex]The last equation is the rectangular equation we were looking for.