Solution:
The area of a sector is expressed as
[tex]\begin{gathered} area\text{ of sector = }\frac{\theta}{360}\times\pi r^2 \\ \Rightarrow area\text{ of sector = }\frac{\theta}{360}\times area\text{ of circle} \end{gathered}[/tex]Given that the circle has an area of 24 square meters, and has a 45 degree sector, this implies that
[tex]\begin{gathered} area\text{ of sector =}\frac{45}{360}\times24 \\ =3\text{ m}^2 \end{gathered}[/tex]Hence, the area of the sector is
[tex]3\text{ m}^2[/tex]
