How many moles of Pb(NO3)2 are requiredif 12 moles of AI(NO3)3 are produced?3Pb(NO3)2 + 2AlCl3 → 3PbCl2 + 2AI(NO3)3

Answer
18 moles Pb(NO₃)₂
Explanation
Given:
Moles of AI(NO₃)₃ produced = 12 moles
Equation: 3Pb(NO₃)₂ + 2AlCl₃ → 3PbCl₂ + 2AI(NO₃)₃
What to find:
The moles of Pb(NO₃)₂ required to produce 12 moles of AI(NO₃)₃.
Solution:
Let the moles of Pb(NO₃)₂ required be represented as x.
From the given equation;
3 moles Pb(NO₃)₂ produced 2 moles AI(NO₃)₃
x moles Pb(NO₃)₂ will produce 12 moles AI(NO₃)₃
Cross multiply and divide both sides by 2 moles AI(NO₃)₃
[tex]x=\frac{12\text{ }moles\text{ }Al\left(NO₃\right)₃}{2\text{ }moles\text{ }Al\left(NO₃\right)₃}\times3\text{ }moles\text{ }Pb(NO_3)_2=18\text{ }moles\text{ }Pb(NO_3)_2[/tex]Therefore, 18 moles of Pb(NO₃)₂ are required to produce 12 moles of AI(NO₃)₃.