Given the equation below.
[tex]\frac{v+2}{v-1}=\frac{v-2}{v+3}[/tex]Cross Multiply
[tex]\begin{gathered} (v+2)(v+3)=(v-2)(v-1) \\ v^2+3v+2v+6=v^2-v-2v+2 \end{gathered}[/tex][tex]v^2+5v+6=v^2-3v+2[/tex][tex]\begin{gathered} collect\text{ like terms} \\ v^2-v^2+5v+3v=2-6 \\ 8v=-4 \\ v=-\frac{4}{8}=-\frac{1}{2} \end{gathered}[/tex]Hence, the value for v = -1/2
