Question

If part of an electric circuit dissipates energy at 6 W when it draws a current of 3 A, what voltage is impressed across it?

Answer 1

We will have the following:

First, we recall that:

$V=\frac{P}{I}$

So:

$V=\frac{6W}{3A}\Rightarrow V=2V$

So, the voltage is 2 Volts.