Question

The question is: write an expression for the combined area of the three gardens in plan a and of the three gardens in plan b. Show two different ways to write each expression. Area for plan a:Area for plan b: There are previous answers that we already have that might help with this question so I have to send them as well but this is the question I need answered.

Answer 1

So,

For plan A, we got that:

If all the fence is 480 ft, then, we know that the length of all the three gardens is:

$4x+6y=480$

Where if we solve for y, we got that:

$\begin{gathered} 6y=480-4x \\ y=80-\frac{2}{3}x \end{gathered}$

Now, remember that the area of a rectangle is given by multiplying its width and large. The width of the rectangle formed by the three gardens is "x" and its large is "3y". We know that y = 80 - 2/3x, so:

$\begin{gathered} A(x)=3y\cdot x \\ A(x)=3(80-\frac{2}{3}x)(x) \\ A(x)=(240-2x)x \\ A(x)=240x-2x^2 \end{gathered}$

So that's an expression for the combined area of the three gardens in plan a.

For plan b, we're given that:

The length of the combined gardens is given by:

$5x+5y=480$

Wher