Question

solve the system of linear equations by substitution 1/2x+2y=3 and 6y+1=x

Answer 1

Given:

$\begin{gathered} \frac{1}{2}x+2y=3 \\ -1x+6y=-1 \end{gathered}$

Requirement:

Solution of the equations

Explanation:

$\begin{gathered} \frac{1}{2}x+2y=3 \\ -\frac{1}{2}x+\frac{6}{3}y=-\frac{1}{2} \end{gathered}$

by adding

$\begin{gathered} 4y=\frac{5}{2} \\ y=\frac{5}{8} \end{gathered}$

putting the value of y in first equation

$\begin{gathered} \frac{1}{2}x+2\times\frac{5}{8}=3 \\ x=3.5 \end{gathered}$

Final Answer:

x = 0.625

y = 3.5