Can you help me with 1 please thanks Round to the next tenth

x is the hypotenuse of the right triangle. To find it, use the formula for hypotenuse:
[tex]h^2=a^2+b^2[/tex]Where:
h = hypotenuse.
a and b = sides.
In this exercise,
h = x.
a = 8.
b = 3.
So, substituting the values:
[tex]x^2=8^2+13^{2^{}}[/tex]And solving the operations:
[tex]\begin{gathered} x^2=64+169 \\ x^2=233 \end{gathered}[/tex]And taking the root from both sides.
[tex]\begin{gathered} \sqrt[]{x^2}=\sqrt[]{233} \\ x=15.3 \end{gathered}[/tex]