Question

If an object is 15.31 cm in front of a convex mirror that has a focal length of 58.25 cm, how far behind the mirror will the image appear to an observer ?

Answer 1

ANSWER

12.12 cm

EXPLANATION

Given:

• The mirror is convex

,

• The object distance, u = -15.31 cm

,

• The focal length, f = +58.25 cm

Find:

• The image distance, v

Using the mirror equation,

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

And solving for v we have,

$v=\frac{1}{\frac{1}{f}-\frac{1}{u}}=\frac{1}{\frac{1}{58.25}-\frac{1}{-15.31}}\approx12.12cm$

Hence, the image will appear 12.12 cm behind the mirror.