If the volume of a sample of gas is increased 5 times the original volume while the temperature is held constant, what happens to the pressure of the gas?
A. It decreases by 1/5.
B. It increases by 1/5.
C. It increases 5 times the original pressure.
D. It stays the same.

Respuesta :

The answer is C, I hope this answers your question :)

The final pressure of the gas decreases by 1/5 of the original pressure of the gas.

Given:

If the volume of a sample of gas is increased 5 times the original volume while the temperature is held constant,

To find:

The change in pressure of the gas.

Solution:

The initial volume of the gas = [tex]V_1[/tex]

The initial pressure of the gas = [tex]P_1[/tex]

The final volume of the gas = [tex]V_2=5V_1[/tex]

The final pressure of the gas = [tex]P_2=?[/tex]

Using Boyles law:

[tex]P_1V_1=P_2V_2\\\\P_2=\frac{P_1V_1}{V_2}\\\\P_2=\frac{P_1V_1}{5V_1}\\\\P_2=\frac{P_1}{5}[/tex]

The final pressure of the gas decreases by 1/5 of the original pressure of the gas.

Learn more about Boyles law here:

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