Using the basic theorem of proportionality, we can express the following
[tex]\frac{BD}{AD}=\frac{CE}{AE}[/tex]Using the given information, we have
[tex]\frac{3}{2+3}=\frac{4}{AE}[/tex]Let's solve for AE
[tex]\begin{gathered} AE=\frac{4\cdot5}{3} \\ AE=\frac{20}{3} \\ AE=6\frac{2}{3} \end{gathered}[/tex]