Question

For a standard normal distribution, find P(z< c) = 0.9089 find c rounded to two decimal places

Answer 1

$c\text{ = -1.33}$

Here, we want to find the value of c for which the given probability equals the given value

All we have to do here is to find the z-score that corresponds to this value

To do this, we can use the standard normal distribution table

Alll we have to do is to get the z-score that corresponds to the given probability

By the use of the standard normal distribution table, the value of c that correlates to this particular probability value is -1.334

To 2 decimal places, this is -1.33