Question

If the frequency of an oscillator is 9.4 Hz, calculate the tie period T

Answer 1

Answer:

The period, T = 0.106 seconds

Explanation:

The frequency, F = 9.4 Hz

Let the period be represented by T

The relationship between frequency and period is given as:

$T=\frac{1}{F}$

Substitute F = 9.4 Hz into the relationship above

$\begin{gathered} T=\frac{1}{9.4} \\ T=0.106\text{ seconds} \end{gathered}$

Therefore, the period, T = 0.106 seconds