Substituting each ordered pair we have the following
a.) (2,7)
[tex]\begin{gathered} \text{IF }(x,y)=(2,7)\text{ THEN} \\ y=3x-1 \\ 7\questeq3(2)-1 \\ 7\questeq6-1 \\ 7\neq5 \end{gathered}[/tex]b.) (0,-1)
[tex]\begin{gathered} \text{IF }(x,y)=(0,-1)\text{ THEN} \\ y=3x-1 \\ -1\questeq3(0)-1 \\ -1=-1\checkmark \end{gathered}[/tex]c.) (0,1)
[tex]\begin{gathered} \text{IF }(x,y)=(0,1)\text{ THEN} \\ y=3x-1 \\ 1\questeq3(0)-1 \\ 1\neq-1 \end{gathered}[/tex]d.) (2,5)
[tex]\begin{gathered} \text{IF }(x,y)=(2,5)\text{ THEN} \\ y=3x-1 \\ 5\questeq3(2)-1 \\ 5\questeq6-1 \\ 5=5\checkmark \end{gathered}[/tex]e.) (-1,-4)
[tex]\begin{gathered} \text{IF }(x,y)=(-1,-4)\text{ THEN} \\ y=3x-1 \\ -4\questeq3(-1)-1_{} \\ -4\questeq-3-1 \\ -4=-4\checkmark \end{gathered}[/tex]Therefore, the coordinates that satisfies the equation y = 3x - 1 are (0,-1), (2,5), and (-1,-4)