Question

3÷2+45-90×100+2021÷2001=

Answer 1

Explanation:

First we have to separate this expression in terms. The terms are delimited by + or - signs. I'll add parenthesis to separate the terms:

$(3\div2)+(45)-(90\times100)+(2021\div2001)$

Now we have to solve the expressions inside each parenthesis first:

$(\frac{3}{2})+(45)-(9000)+(\frac{2021}{2001})$

We have fractions in this expression. To do the additions and substractions we have to find the lowest common denomination. Since the denominators we have are 2 and 2001, and 2001 is not divisible by 2, the lowest common denominator is 2001x2=4002:

$\begin{gathered} \frac{3}{2}+45-9000+\frac{2021}{2001} \\ \frac{3\times2001+45\times4002-9000\times4002+2\times2021}{4002} \end{gathered}$

Now we have to separate the terms again for the numerator:

$\frac{(3\times2001)+(45\times4002)-(9000\times4002)+(2\times2021)}{4002}$

And solve what's inside each parenthesis:

$\frac{(6,003)+(180,090)-(36,018,000)+(4,042)}{4,002}$

And add:

$\frac{-35,827,865}{4,002}=-8,952.49$

Answer:

3÷2+45-90×100+2021÷2001 =​ -8952.49