Question

Factoring to find the zeros 1. x^2-11x+19=-5 2. n^2+7n+15=5 Completing the square to find the zeros 3. a^2+2a-3=0 4. a-2a-8=0Quadratic formula to find the zeros5. m^2-5m-14=06. b^2-4b+4=0

Answer 1

Let's factor the first equation:

$x^2-11x+19=-5$

first we need to write all the terms in the same side, then we have:

$\begin{gathered} x^2-11x+19+5=0 \\ x^2-11x+24=0 \end{gathered}$

now we factor the left side:

$(x-3)(x-8)=0$

this implies that:

$\begin{gathered} x-3=0 \\ x=3 \\ or \\ x-8=0 \\ x=8 \end{gathered}$

Therefore the solutions for the equation are x=3 and x=8