x^2 = 6y
The equation is for a parabola
The standard form is 4p(y-k) = (x-h)^2
We can tell the vertex is (0,0)
Rewriting the standard form
4p(y) = x^2
Setting 4p = 6
Solving for p
p = 6/4 = 3/2
To find the focus, add p to the vertex. Since this is a vertical parabola, add to the y compoent
Since it us upward facing, the focus is above the vertex
(0, 0+3/2) = (0,3/2)
