Given:
the mass of the train is
[tex]m=10^4\text{ kg}[/tex]The webs of the spider stretched by
[tex]x=500\text{ m}[/tex]Required: effective spring constant of the web
Explanation:
to solve this problem we use energy conservation.
when the train is moving with velocity v it has kinetic energy and when the spider tries to stop the train then it will gain potential energy in its webs.
then we have
[tex]\begin{gathered} P.E=K.E \\ \frac{1}{2}kx^2=\frac{1}{2}mv^2 \end{gathered}[/tex]we assume that train is moving with some velocity say 90 km/h.
change it in m/s.
we get
[tex]\begin{gathered} v=\frac{90\times1000\text{ m}}{3600\text{ s}} \\ v=25\text{ m/s} \end{gathered}[/tex]plugging all the values in the above equation, we get
[tex]\begin{gathered} \frac{1}{2}k\times(500\text{ m})^2=\frac{1}{2}\times10^4\text{ kg}\times(25\text{ m/s})^2 \\ k=\frac{10^4\text{ }\times625\text{ }}{25\times10^4} \\ k=25\text{ N/m} \end{gathered}[/tex]Thus, the effective spring constant is 25 N/m.