Given:
Initial velocity = 11 m/s
Average acceleration = -1.81 m/s²
Let's determine how long it takes the horse to decrease its velocity to 6.5 m/s.
Apply the equation of motion:
[tex]v=u+at[/tex]Where:
v is the final velocity = 6.5 m/s
u is the initial velocity = 11 m/s
a is the acceleration = -1.81 m/s²
t is the time in seconds.
Thus, we have:
[tex]\begin{gathered} 6.5=11+(-1.81)t \\ \\ 6.5=11-1.81t \end{gathered}[/tex]Let's solve for t.
Subtract 11 from both sides:
[tex]\begin{gathered} 6.5-11=11-11-1.81t \\ \\ -4.5=-1.81t \\ \\ \text{Divide both sides by -1.81:} \\ \frac{-4.5}{-1.81}=\frac{-1.81t}{-1.81} \\ \\ 2.49=t \\ \\ t=2.49\text{ seconds} \end{gathered}[/tex]Therefore, it took the horse approximately 2.49 seconds to decrease its velocity to 6.5 m/s
ANSWER:
2.49 seconds.