Question

The table shows the classification of students in a school

Answer 1

Given:

Given a table showing the classification of students

Required: Probability

Explanation:

i) From the table, the total number of students in the school

$\begin{gathered} =45+40+60+55+50+35+65+50+70+55+45+30 \\ =600 \end{gathered}$

a) Number of boys in the school

$\begin{gathered} =45+60+50+65+70+45 \\ =335 \end{gathered}$

Probability of selecting a boy from the school

$\begin{gathered} =\frac{335}{600} \\ =\frac{67}{120} \end{gathered}$

(b) Number of girls in the school

$\begin{gathered} =40+35+55+55+50+30 \\ =265 \end{gathered}$

Probability of selecting a girl from the school

$\begin{gathered} =\frac{265}{600} \\ =\frac{53}{120} \end{gathered}$

ii)

a) Number of boarders in SS1

$\begin{gathered} =60+55 \\ =115 \end{gathered}$

Probability of selecting a boarder in SS1

$\begin{gathered} =\frac{115}{600} \\ =\frac{23}{120} \end{gathered}$

b) Number of girls in boarding

$\begin{gathered} =55+50+30 \\ =135 \end{gathered}$

Probability of selecting a boarder that is a girl

$\begin{gathered} =\frac{135}{600} \\ =\frac{9}{40} \end{gathered}$

Final Answer:

i) a) Probability of selecting a boy from the school = 67/120

b) Probability of selecting a girl from the school = 53/120

ii) a) Probability of selecting a boarder in SS1 = 23/120

b) Probability of selecting a boarder that is a girl = 9/40