Question

I am going to show you the picture and then I'm going to show you the problem

Answer 1

Solution

a)Using Congruency of angles and sides (SSS)(Side Side Side) and AAA(Angle Angle Angle) respectively, We have

$AC\cong FH$$AB\cong FG$$BC\cong HG$$\begin{gathered} Angle\text{CAB}\cong AngleHFG \\ \text{Angle CBA}\cong Angle\text{ HGF} \\ \end{gathered}$$\text{Angle ACB}\cong Angle\text{ FHG}$

b) The transformation is reflective of the x-axis. Triangle ABC is the inverted form of triangle FGH