Question

The sides of a triangle have lengths 7,8, and 10. What is the lengih of the shortest side of a similar triangle whose perimeter is 75

Answer 1

$\begin{gathered} P1=7+8+10=25 \\ P2=75 \end{gathered}$

the shortest side of P1 is 7

$\begin{gathered} \frac{7}{25}=\frac{x}{75} \\ 7\cdot75=25x \\ \frac{525}{25}=x \\ 21=x \end{gathered}$