The radius of a cylindrical construction pipe is 2 ft. If the pipe is 17 ft long, what is its volume?Use the value 3.14 for it, and round your answer to the nearest whole number.Be sure to include the correct unit in your answer.2 ftco17 ft

The radius of a cylindrical construction pipe is 2 ft If the pipe is 17 ft long what is its volumeUse the value 314 for it and round your answer to the nearest class=

Respuesta :

We know that the volumen is

[tex]v=\text{ area of the base}\cdot length(height)[/tex]

In this case, the base is a circumferecen. So, the area of the base is

[tex]\text{ area of the base}=\pi\cdot r^2[/tex]

Now, the volume of the cylindrical construction is

[tex]v=\pi\cdot r^2\cdot length(height)[/tex]

Where,

[tex]\begin{gathered} \pi=3.14 \\ r=2ft\text{ is the radius of the circumference} \\ \text{length}=17ft \end{gathered}[/tex]

Replacing the values in the eqution for the volume we obtain

[tex]v=(3.14)(2ft)^2(17ft)[/tex]

Solving the multiplications

[tex]v=213.52ft^3[/tex]

Finally, rounding the answer to the nearest whole number

[tex]v=213.52ft^3\approx214ft^3[/tex]

ANSWER:

[tex]214ft^3[/tex]

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