The given expressions are
[tex]\begin{gathered} 6(a+2) \\ 6a+12 \\ 3(2a+4) \end{gathered}[/tex]We use the distributive property to solve the first and third expression.
[tex]\begin{gathered} 6(a+2)=6a+12 \\ 3(2a+4)=6a+12 \end{gathered}[/tex]Notice that all three expressions are equivalent.