Given:
To rent a certain meeting room, a college charges a reservation fee of $39 and an additional fee of $8.40 per hour.
Let the number of hours = t and the total fee = F
So,
[tex]F\ge8.4t+39[/tex]The chemistry club wants to spend less than $72.60 on renting the meeting room.
So, substitute with F = 72.6 and solve for t
[tex]\begin{gathered} 72.6\ge8.4t+39 \\ 72.6-39\ge8.4t \\ 33.6\ge8.4t \\ \frac{33.6}{8.4}\ge t \\ \\ 4\ge t \end{gathered}[/tex]so, the answer will be time should not exceed 4 hours