Given:
[tex]\begin{gathered} n=100 \\ p=0.15 \\ z=1.96 \end{gathered}[/tex]
Required:
To find the margin error.
Explanation:
The formula for margin error is
[tex]\begin{gathered} =z\times\sqrt{\frac{p(1-p)}{n}} \\ \\ =1.96\times\sqrt{\frac{0.15(1-0.15)}{100}} \\ \\ =1.96\times\sqrt{0.001275} \\ \\ =1.96\times0.03570 \\ \\ =0.0699 \\ \\ \approx0.0700 \end{gathered}[/tex]
Final Answer:
The option B is correct.
[tex]0.0700[/tex]
