Question

Parents are having triplet babies and have put 6 unique name cards in a bowl.* When the first baby is born, a parent draws a card and gives the baby that name.* When the second baby is born, the parent draws a card from the remaining names.* When the third baby is born, the parent draws a card from the remaining names.How many combinations of names were possible for those three babies?

Answer 1

Given

6 unique name cards in a bowl.

First 6

second 5

Third 4

Solution

$6\times5\times4=120$

120 combinations of names