Question

Find the zeros of the following quadratic equation:y = x^2-3x-18A.) -3, -6B.) 3, -6C.) 3, 6D.) -3, 6

Answer 1

we have the quadratic equation

$y=x^2-3x-18$

using the formula

a=1

b=-3

c=-18

substitute given values

$x=\frac{-(-3)(+_-)\sqrt{-3^2-4(1)(-18)}}{2(1)}$$x=\frac{3(_{+\-})9}{2}$

The values of x are

x=6 and x=-3

the answer is option D