Given the sequence below,
[tex]6,24,96,384,\ldots[/tex]The sequence is a geometric sequence whose formula is given below as,
[tex]Un_{}=ar^{n-1}[/tex]To find the common ratio, r,
[tex]\begin{gathered} r=\frac{2^{nd}\text{ term}}{1^{st}\text{ term}}\text{ or }\frac{3^{rd}\text{ term}}{2^{nd}\text{ term}} \\ \text{Where the 2}^{nd\text{ }}term=24,1^{st}\text{ term=6} \\ r=\frac{24}{6}=4 \end{gathered}[/tex]To find the nth term of the sequence,
[tex]\begin{gathered} \text{Where a=6 and r=4} \\ U_n=6(4)^{n-1} \end{gathered}[/tex]To find the 7th,
[tex]\begin{gathered} \text{Where n=7, a=6 and r=4} \\ U_7=6(4)^{7-1}=6(4)^6=6\times4096=24576 \end{gathered}[/tex]Hence, the nth term is 6(4)ⁿ⁻¹ and
The 7th term is 24576