Question

Evaluate the trigonometric function using its periods as an aid.

Answer 1

Weh ave the following:

$\sin \mleft(-\frac{19\pi}{6}\mright)$

we evaluate:

$\begin{gathered} \sin (-\frac{19\pi}{6})=-\sin (\frac{19\pi}{6})=-\sin (\frac{7\pi}{6})=-(\frac{1}{2}) \\ \sin (-\frac{19\pi}{6})=\frac{1}{2} \end{gathered}$