you need to have a password with 5 letters followed by 3 odd digits between 0 and 9, inclusive. if the characters and digits cannot be used more than once, how many choices do you have for your password?

It is clear from mathematical and statistical logic that the question was written incorrectly and that some of the digits were repeated. Thus, the appropriate query is:

"You need to have a password with 5 letters followed by 3 odd digits between 0 and 9, inclusive. If the characters and digits cannot be used more than once, how many choices do you have for your password?"

So,

We can write,

We all know that there are 26 letters available in the alphabet and there are just 5 numbers between 0 and 9.

We are now given the situation of how many passwords can we make out of the criteria of having 5 letters that cannot be repeated and 3 odd digits from 0-9.

We cannot repeat the numbers and letters, thus our password will look something like this, LLLLLNNNN, where L is a letter and N is a number. Let us note that we cannot use the characters and digits more than once.

This is how we will solve the probable number of passwords.

= 26 x 25 x 24 x 23 x 22 x 5 x 4 x 3

5 letters from 26 with no repetition => 26*25*24*23*22 different choices.

Odd digits are 1, 3, 5, 7 and 9 => 5 different digits to choose

3 digits from 5 with no repetition => 5*4*3 = 60

Then, the total number of choices is: 26*25*24*23*22*60 = 473,616,000

Therefore,

You need to have a password with 5 letters followed by 3 odd digits between 0 and 9, inclusive, then the used choices are = 473,616,000

To learn more about information visit Odd digits problems :

brainly.com/question/5424891

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