The surface area of a cube is given by:
[tex]SA=6\cdot l^2[/tex]where:
l = length of one of the sides
so:
[tex]12868=6l^2[/tex]solve for l:
[tex]\begin{gathered} l=\sqrt[]{\frac{12868}{6}} \\ l\approx46.31 \end{gathered}[/tex]The length of a diagonal that is not a diagonal of a face is:
[tex]\begin{gathered} d=\sqrt[]{3}l \\ d\approx80.21 \end{gathered}[/tex]