Question

Based on the record for the past several seasons, a sports fan believes the probability that the red team will win a given game is 3/5. The fan also believes the probability that the blue team wins and giving game is 11/20. As compared to the blue team, how many more games should the fan expect the red team to win during a 180-game season ? Explain.

Answer 1

$\begin{gathered} \frac{3}{5}=0.6 \\ \frac{11}{20}=0.55 \end{gathered}$

Therefore, the probability that the red team wins is 60%, and the probability that the blue team wins is 55%, based on this we can conclude for a 180-game season:

$180\times0.6=108$

The fan expect the red team wins 108 games

For the blue team:

$180\times0.55=99$

As compared to the blue team, the red team:

$108-99=7$

Will win 7 games more than the blue team