Respuesta :
nealmiyasmith20, this is the solution:
-2× + 5y= -1
3× + 2y= 11
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Step 1: Isolating x on the first equation:
-2× + 5y= -1
-2x = - 1 - 5y
Dividing by -2 at both sides:
-2x/-2 = -1/-2 - 5y/-2
x = 1/2 + 5y/2
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Step 2: Substituting x and solving for y on the second equation:
3× + 2y = 11
3 ( 1/2 + 5y/2) + 2y = 11
3/2 + 15y/2 + 2y = 11
19y/2 = 11 -3/2
19y/2 = 19/2
Multiplying by 2/19 at boths sides:
19y/2 *2/19 = 19/2 * 2/19
y = 1
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Step 3: Substituting y and solving for x on the first equation:
-2× + 5y = -1
-2x + 5 * 1 = -1
-2x + 5 = -1
-2x = -1 - 5
-2x = -6
Dividing by -2 at both sides:
-2x/-2 = -6/-2
x = 3
Step 4: Proving that x = 3 and y = 1 are correct on the second equation:
3× + 2y = 11
3 * 3 + 2 * 1 = 11
9 + 2 = 11
11 = 11
We proved that x = 3 and y = 1 are correct
