given the function
[tex]-2x^2+11x-15=0[/tex]given the quadratic formula
[tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]where
a= - 2
b= 11
c= - 15
to find the number of solution we focus on the root
[tex]\sqrt{b^2-4ac}[/tex][tex]\sqrt{11^2-4(-2)(-15)}[/tex][tex]\sqrt{121-120}[/tex][tex]\sqrt{1}=1[/tex]since the root is a rational number different than 0
the function has Two distinct rational solutions