We have the expression:
[tex]3s^2+10s+7[/tex]We factor as follows:
[tex]\Rightarrow(s+1)(3s+7)[/tex]***
We know that the expression when factored is the product of two smaller expressions that give as solution the original expression. We also know that in each expression s is present and in each expression, there is a compliment, so they have the form:
[tex](as+b)(cs+d)=3s^2+10s+s[/tex]We concentrate in the "extremes" of the trinomial (these being 3s^2 and 7).
We know that each is the product of two different values.
So 3s^2 is the product of as*cs, and we can rapidly see that as = s and