Question

A block of weight W is pushed to the right across a level surface at a constant velocity by a force P acting at an angle above the horizontal, as shown. The magnitude of the normal force exertedon the block by the surface is

Answer 1

ANSWER:

(a)

$w+P\cdot\sin \theta$

STEP-BY-STEP EXPLANATION:

The first thing is to make the force diagram to be able to determine the answer, just like this:

Therefore, in the y-direction, we can determine the value of the normal force as follows:

$N=w+P\cdot\sin \theta$