Answer:
x > -1
Step-by-step explanation:
We have:
[tex]1+x>2\cdot(-2-5x)+6x[/tex]In order to solve for x, we have to isolate x.
To do this, we begin solving each side:
[tex]\begin{gathered} 1+x>-4-10x+6x \\ 1+x>-4-4x \end{gathered}[/tex]To the inequality keep being true, we have to do the same thing with both sides of the equation.
So, let's sum -1 in both sides:
[tex]\begin{gathered} 1+x-1>-4-4x-1 \\ x>-5-4x \end{gathered}[/tex]Now let's sum +4x on both sides:
[tex]\begin{gathered} x+4x>-5-4x+4x \\ 5x>-5 \end{gathered}[/tex]Finally, let's divide both sides by 5:
[tex]\begin{gathered} \frac{5x}{5}>-\frac{5}{5} \\ x>-1 \end{gathered}[/tex]Answer:
[tex]x>-1[/tex]