Let be "t" the number of ten-dollar bills they have and "w" the number of twenty-dollar bills they have.
Using the information given in the exercise, you can set up the following System of Equations:
[tex]\begin{cases}10t+20w=430 \\ t=30-w\end{cases}[/tex]To solve the System of Equations, you can apply the Substitution Method:
1. Substitute the second equation into the first one:
[tex]10(30-w)+20w=430[/tex]2. Solve for "w":
[tex]\begin{gathered} 300-10w+20w=430 \\ 10w=430-300 \\ \\ w=\frac{130}{10} \\ \\ w=13 \end{gathered}[/tex]3. Substitute the value of "w" into the second original equation:
[tex]t=30-(13)[/tex]4. Finally, evaluating, you get:
[tex]t=17[/tex]Therefore, the answer is: They have 17 bills of $10 and 13 bills of $20.