Respuesta :

Answer:

(-3,-4)

Explanation:

Given the system of equations:

[tex]\begin{gathered} y=x-1\cdots(1) \\ 4x+8=y\cdots(2) \end{gathered}[/tex]

Substitute equation (1) into equation (2):

[tex]\begin{gathered} 4x+8=y\operatorname{\cdots}(2) \\ 4x+8=x-1 \end{gathered}[/tex]

Solve the resulting equation for x:

[tex]\begin{gathered} \text{Subtract x from both sides:} \\ 4x-x+8=x-x-1 \\ 3x+8=-1 \\ \text{Subtract 8 from both s}\imaginaryI\text{des} \\ 3x+8-8=-1-8 \\ 3x=-9 \\ \text{ Divide both sides by 3} \\ \frac{3x}{3}=-\frac{9}{3} \\ x=-3 \end{gathered}[/tex]

Using equation (1), solve for y:

[tex]\begin{gathered} y=x-1 \\ =-3-1 \\ =-4 \end{gathered}[/tex]

The solution to the system of linear equation is (x,y)=(-3,-4).

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