Question

In the ordered pair (1,6), which number tells me how far I will jump?

Answer 1

Given the following plot on the graph

(8, 7)

Accoring to the point, run = 8 and rise = 7

$\begin{gathered} \text{Distance = }\sqrt[]{x^2+y^2} \\ \text{x = 8 and y = 7} \\ \text{Distance = }\sqrt[]{8^2+7^2} \\ \text{Distance = }\sqrt[]{64\text{ + 49}} \\ \text{Distance = }\sqrt[]{113} \\ \text{Distance = }10.63\text{ units} \\ \text{The distance jumped is 10.63 units} \end{gathered}$

Using, pythagora's theorem

Let the distance be d

$\begin{gathered} d\text{ = }\sqrt[]{x^2+y^2} \\ \text{d = }\sqrt[]{1^2+6^2} \\ d\text{ = }\sqrt[]{\text{1 + 36}} \\ \text{d = }\sqrt[]{37} \\ \text{d = }6.1\text{ units} \end{gathered}$

From the ordered pair, (1, 6)

number 1 shows how it run and 6 shows how he jumps

The answer is 6