Question

Find the sum of the first 10 terms of the following series, to the nearest integer.24,96,384, ...

Answer 1

$s\text{ }=\frac{a(r^n-1)^{}}{r-1}$

a = 24

n= 10

r = 96/24 = 4

Replacing:

$s=\frac{24(4^{10}-1)}{4-1}=\frac{24\cdot1,048,575}{3}$

s = 8,388,600