Step 1: Write out the function given
[tex]f(x)=3x^2-x[/tex]Step 2: Interprete the question given
[tex]\sum ^5_{k\mathop=1}f(\frac{k}{2})[/tex]The question requested we find the summation of the first five terms for f(k/2), when k is 1, 2, 3, 4, and 5
Step 3: Find the expression for f(k/2)
[tex]\begin{gathered} f(\frac{k}{2})=3(\frac{k}{2})^2-\frac{k}{2} \\ =\frac{3k^2}{4}-\frac{k}{2} \\ =\frac{3k^2-2k}{4} \end{gathered}[/tex][tex]\begin{gathered} =\frac{3(1)^2-2(1)}{4}+\frac{3(2)^2-2(2)}{4}+\frac{3(3)^2-2(3)}{4}+\frac{3(4)^2-2(4)}{4}+\frac{3(5)^2-2(5)}{4} \\ =\frac{1+8+21+40+65}{4} \\ =\frac{135}{4} \\ =33.75 \end{gathered}[/tex]
Hence, the answer is 33.75