Simplify the equation to obtain the value of x.
[tex]\begin{gathered} x^2-5x+3=x-6 \\ x^2-6x+9=0 \\ x^2-3x-3x+9=0 \\ x(x-3)-3(x-3)=0 \\ (x-3)(x-3)=0 \\ x=3 \end{gathered}[/tex]Substitute 3 for x in equation y = x - 3 to obtain the value of y.
[tex]\begin{gathered} y=3-6 \\ =-3 \end{gathered}[/tex]So solution of equation is (3,-3).
Thus there is one solution for system of equations.